In this primetime event series, the three highest money winners in Jeopardy! history — Ken Jennings, Brad Rutter, and James Holzhauer — will compete to determine the ultimate champion. Alex Trebek hosts.
On the heels of the iconic Tournament of Champions, “JEOPARDY!” is coming to ABC in a multiple consecutive night event with “JEOPARDY! The Greatest of All Time,” premiering Tuesday, January 7 (8:00-9:00PM EST), on ABC. Hosted by Alex Trebek.
“JEOPARDY! The Greatest of All Time” is produced by Sony Pictures Television. Harry Friedman will executive produce. This epic television event brings together the three highest money winners in the long-running game show’s history: Ken Jennings, Brad Rutter, and James Holzhauer. The “JEOPARDY!” fan favorites will compete in a series of matches; the first to win three receives $1 million and the title of “JEOPARDY! The Greatest of All Time.” The two runners up will each receive $250,000.
![ID Unveils Premiere Date for “A Killer Among Friends,” New True Crime Series Narrated and Executive Produced by Jennifer Love Hewitt [VIDEO]](https://mortystv.com/blog/wp-content/uploads/2025/06/Killer-Among-Friends-350x250.webp)
![Official Disney+ Trailer for “People and Places” [VIDEO]](https://mortystv.com/blog/wp-content/uploads/2025/06/People-and-Places-350x250.webp)
![New Series! “Party of Five” Wednesday, January 8 @ 9PM on Freeform [VIDEO]](https://mortystv.com/blog/wp-content/uploads/2020/01/party-of-five.jpg){kind=small}
